Sources / Lambert et al. 2005
Lambert et al. 2005
Canadian national tree aboveground biomass equations
Lambert, M.-C., Ung, C.-H., Raulier, F. (2005). Canadian national tree aboveground biomass equations. Canadian Journal of Forest Research, 35(8), 1996–2018.
Checked 2026-11-01. Crossref is asked weekly for retraction or correction notices; none recorded.
5 equations from this source
- Canadian national equation, black spruce, dbh only (sum of wood, bark, branches, foliage; Table 3)
Aboveground biomass · Picea mariana · Canada · DBH · DBH 1.6–37.2 cm · 1,534 trees
y wood = β wood1 D^βwood2 + ewood … y bark = β bark1 D^βbark2 + e bark … y foliage = β foliage1 D^βfoliage2 … y branches = β branches1 D^βbranches2As printed (Eq. 2)
- Canadian national equation, jack pine, dbh only (sum of wood, bark, branches, foliage; Table 3)
Aboveground biomass · Pinus banksiana · Canada · DBH · DBH 1.7–41 cm · 364 trees
y wood = β wood1 D^βwood2 + ewood … y bark = β bark1 D^βbark2 + e bark … y foliage = β foliage1 D^βfoliage2 … y branches = β branches1 D^βbranches2As printed (Eq. 2)
- Canadian national equation, red oak, dbh only (sum of wood, bark, branches, foliage; Table 3)
Aboveground biomass · Quercus rubra · Canada · DBH · DBH 1.1–55.3 cm · 117 trees
y wood = β wood1 D^βwood2 + ewood … y bark = β bark1 D^βbark2 + e bark … y foliage = β foliage1 D^βfoliage2 … y branches = β branches1 D^βbranches2As printed (Eq. 2)
- Canadian national equation, sugar maple, dbh only (sum of wood, bark, branches, foliage; Table 3)
Aboveground biomass · Acer saccharum · Canada · DBH · DBH 2–57.8 cm · 235 trees
y wood = β wood1 D^βwood2 + ewood … y bark = β bark1 D^βbark2 + e bark … y foliage = β foliage1 D^βfoliage2 … y branches = β branches1 D^βbranches2As printed (Eq. 2)
- Canadian national equation, trembling aspen, dbh only (sum of wood, bark, branches, foliage; Table 3)
Aboveground biomass · Populus tremuloides · Canada · DBH · DBH 0.7–47.2 cm · 773 trees
y wood = β wood1 D^βwood2 + ewood … y bark = β bark1 D^βbark2 + e bark … y foliage = β foliage1 D^βfoliage2 … y branches = β branches1 D^βbranches2As printed (Eq. 2)